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MySQL_项目7: 各部门工资最高的员工(难度:中等)

时间:2019-09-10 17:25:39

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MySQL_项目7: 各部门工资最高的员工(难度:中等)

项目七: 各部门工资最高的员工(难度:中等)

创建Employee表,包含所有员工信息,每个员工有其对应的Id, salary 和 department Id。

+----+-------+--------+--------------+

| Id | Name | Salary | DepartmentId |

+----+-------+--------+--------------+

| 1 | Joe | 70000 | 1 |

| 2 | Henry | 80000 | 2 |

| 3 | Sam | 60000 | 2 |

| 4 | Max | 90000 | 1 |

+----+-------+--------+--------------+

-- 创建employee表CREATE TABLE employee (id int(11) NOT NULL,name varchar(50) NOT NULL,salary decimal(10,2) NOT NULL DEFAULT '0.00',departmentid int(11) NOT NULL,PRIMARY KEY (`id`));-- 插入数据INSERT INTO `employee` VALUES ('1', 'Joe', '70000.00', '1');INSERT INTO `employee` VALUES ('2', 'Herry', '80000.00', '2');INSERT INTO `employee` VALUES ('3', 'Sam', '60000.00', '2');INSERT INTO `employee` VALUES ('4', 'Max', '90000.00', '1');INSERT INTO `employee` VALUES ('5', 'Janet', '69000.00', '1');INSERT INTO `employee` VALUES ('6', 'Randy', '85000.00', '1');INSERT INTO `employee` VALUES ('7', 'sherry', '90000.00', '1');INSERT INTO `employee` VALUES ('8', 'haha', '80000.00', '2');INSERT INTO `employee` VALUES ('9', 'Abbo', '80800.00', '3');

创建Department表,包含公司所有部门的信息。

+----+----------+

| Id | Name |

+----+----------+

| 1 | IT |

| 2 | Sales |

+----+----------+

-- 创建department表CREATE TABLE department (id int(11) NOT NULL,name varchar(100) NOT NULL,PRIMARY KEY (`id`));-- 插入数据INSERT INTO `department` VALUES ('1', 'IT');INSERT INTO `department` VALUES ('2', 'Sales');INSERT INTO `department` VALUES ('3', 'customs');

编写一个 SQL 查询,找出每个部门工资最高的员工。例如,根据上述给定的表格,Max 在 IT 部门有最高工资,Henry 在 Sales 部门有最高工资。

+------------+----------+--------+

| Department | Employee | Salary |

+------------+----------+--------+

| IT | Max | 90000 |

| Sales | Henry | 80000 |

+------------+----------+--------+

注意点:需要考虑同部门最高工资有多个人的情况

SELECT e.*,t.name department,t.maxsalFROM employee eINNER JOIN(SELECT e.departmentid,d.name,MAX(salary) maxsalFROM employee eINNER JOIN department don e.departmentid = d.idGROUP BY e.departmentid,d.name) ton e.departmentid = t.departmentidWHERE e.salary=t.maxsal

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