SELECT(floor( days / 7 )* 5 + days % 7 -CASEWHEN 6 BETWEEN wd AND wd + days % 7-1 THEN1 ELSE 0 END -CASEWHEN 7 BETWEEN wd AND wd + days % 7-1 THEN1 ELSE 0 END ) AS result FROM(select datediff(e,s)+1 as days, weekday(s)+1 as wd ) as a;
e为结束时间,s为开始时间,格式为
-09-02
转载Mysql 编程实战三之计算两个日期的工作日数_数据库_IT虾米网
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