我不太明白，但我可能会有以下两种中的一种，你想要什么 .
1)访问摄像头，只在屏幕上显示视频(不捕获图像)：
html:
js:
var onFailSoHard = function(e)
{
console.log('failed',e);
}
window.URL = window.URL || window.webkitURL ;
navigator.getUserMedia = navigator.getUserMedia || navigator.webkitGetUserMedia;
var video = document.querySelector('video');
if(navigator.getUserMedia)
{
navigator.getUserMedia({video: true},function(stream) {
video.src = window.URL.createObjectURL(stream);
},onFailSoHard);
}
var canvas = document.getElementById('canvas');
var ctx = canvas.getContext('2d');
setInterval(function(){
ctx.drawImage(video,0,0);
}, 100);
}
2)从相机捕获图像：
navigator.camera.getPicture(onSuccess, onFail, { quality: 50,
destinationType: Camera.DestinationType.DATA_URL
});
function onSuccess(imageData) {
var image = document.getElementById('myImage');
image.src = "data:image/jpeg;base64," + imageData;
}
function onFail(message) {
alert('Failed because: ' + message);
}
