200字范文,内容丰富有趣,生活中的好帮手!
200字范文 > 使用java基础完成一个简单的控制台输入的用户管理(包括用户注册 登录 修改密码 及

使用java基础完成一个简单的控制台输入的用户管理(包括用户注册 登录 修改密码 及

时间:2021-09-09 06:20:41

相关推荐

使用java基础完成一个简单的控制台输入的用户管理(包括用户注册 登录 修改密码 及

要求

实体类

//该类为用户对象的实体类

public class User {

private String name;

private String password;

private String email;

public String getName() {

return name;

}

public void setName(String name) {

this.name = name;

}

public String getPassword() {

return password;

}

public void setPassword(String password) {

this.password = password;

}

public String getEmail() {

return email;

}

public void setEmail(String email) {

this.email = email;

}

public User(String name, String password, String email) {

this.email = email;

this.name = name;

this.password = password;

}

public User(String name, String password) {

this.name = name;

this.password = password;

}

}

//该类为存放用户对象的容器对象,在这个对象中有一个User[]的数组容器,用于存放User对象

public class Users {

public static User[] users = new User[20];

public User[] getUsers() {

return users;

}

}

//这个类是写相关功能的逻辑的类,里面有注册(reginst),登录(longin),修改(update)的相关校验及逻辑方法】

public class UserService {

public String reginst(Users users, User user, String password2) {

String mess = null;

int userNumber = 0;

String name = user.getName();

String password = user.getPassword();

if (Utils.userIsExist(users, user)) {

if (4 <= name.length() && name.length() <= 6) {

if ("0".equals(name.subSequence(0, 1)) || "1".equals(name.subSequence(0, 1))

|| "2".equals(name.subSequence(0, 1)) || "3".equals(name.subSequence(0, 1))

|| "4".equals(name.subSequence(0, 1)) || "5".equals(name.subSequence(0, 1))

|| "6".equals(name.subSequence(0, 1)) || "7".equals(name.subSequence(0, 1))

|| "8".equals(name.subSequence(0, 1)) || "9".equals(name.subSequence(0, 1))) {

mess = "用户名请以字母开头";

} else {

if (Utils.isNotDump(name)) {

if (6 <= password.length() && password.length() <= 12) {

if ("0".equals(password.subSequence(0, 1)) || "1".equals(password.subSequence(0, 1))

|| "2".equals(password.subSequence(0, 1)) || "3".equals(password.subSequence(0, 1))

|| "4".equals(password.subSequence(0, 1)) || "5".equals(password.subSequence(0, 1))

|| "6".equals(password.subSequence(0, 1)) || "7".equals(password.subSequence(0, 1))

|| "8".equals(password.subSequence(0, 1))

|| "9".equals(password.subSequence(0, 1))) {

mess = "用户密码请以字母开头";

} else {

if (Utils.containNumber(password)) {

if (userNumber <= 20) {

if (password.equals(password2)) {

Users.users[userNumber] = user;

userNumber++;

mess = "用户注册成功";

} else {

mess = "两次密码输入不一致";

}

} else {

mess = "内存已满,请先删除用户";

}

} else {

mess = "密码必须含有数字";

}

}

} else {

mess = "密码必须为6-12位";

}

} else {

mess = "用户名有重复元素";

}

}

} else {

mess = "用户名必须为4-6位";

}

} else {

mess = "该用户已存在";

}

return mess;

}

@SuppressWarnings("unused")

public String login(Users users, User user) {

String mess = null;

for (int i = 0; i < users.getUsers().length; i++) {

if (users.getUsers()[i].getName().equals(user.getName())

&& users.getUsers()[i].getPassword().equals(user.getPassword())) {

mess = "登录成功";

return mess;

} else {

mess = "用户名或密码错误";

return mess;

}

}

return mess;

}

@SuppressWarnings("unused")

public String update(Users users, User user) {

String mess = null;

for (int i = 0; i < users.getUsers().length; i++) {

if (users.getUsers()[i].getName().equals(user.getName())) {

users.getUsers()[i] = user;

mess = "密码已修改";

return mess;

} else {

mess = "修改密码失败";

return mess;

}

}

return mess;

}

}

//接下来是我们用到的一些相关的工具的类

public class Utils {

// 判断是否存在重复元素

public static boolean isNotDump(String iniString) {

char[] a = iniString.toCharArray();

for (char item : a) {

int index = iniString.indexOf(item);

for (char s : Arrays.copyOfRange(a, index + 1, a.length)) {

if (s == item) {

return false;

}

}

}

return true;

}

// 判断是否包含数字

public static boolean containNumber(String content) {

boolean flag = false;

Pattern p = pile(".*\\d+.*");

Matcher m = p.matcher(content);

if (m.matches()) {

flag = true;

}

return flag;

}

// 判断用户是否已存在

@SuppressWarnings("unused")

public static boolean userIsExist(Users users, User user) {

Boolean falg = true;

if (users.getUsers()[0] == null) {

return falg;

}

for (int i = 0; i < users.getUsers().length; i++) {

if (users.getUsers()[i].getName().equals(user.getName())) {

falg = false;

return falg;

} else {

return falg;

}

}

return falg;

}

}

//最后一个是我们的运行的相关方法

public class run {

private static Scanner key;

public static void main(String[] args) {

init();

}

public static void init() {

show();

System.out.print("请选择操作:");

key = new Scanner(System.in);

String item = key.nextLine();

switch (item) {

case "1":

reginst(); // 增加

break;

case "2":

longin();

break;

case "3":

update(); // modify修改

break;

case "0":

System.out.println("\t退出成功!");

System.exit(0);

default:

System.out.println("输入错误,请重新选择!");

break;

}

}

private static void reginst() {

System.out.println("\t【注册用户】");

System.out.print("\t请输入用户名:");

String name = key.nextLine();

System.out.print("\t请输入用户名邮箱:");

String email = key.nextLine();

System.out.print("\t请输入用户密码:");

String password = key.nextLine();

System.out.print("\t请再次输入用户密码:");

String password2 = key.nextLine();

Users users = new Users();

User user = new User(name, password, email);

UserService userService = new UserService();

String mess = userService.reginst(users, user, password2);

System.out.println(mess);

init();

}

private static void longin() {

System.out.println("\t【注册用户】");

System.out.print("\t请输入用户名:");

String name = key.nextLine();

System.out.print("\t请输入用户密码:");

String password = key.nextLine();

Users users = new Users();

User user = new User(name, password);

UserService userService = new UserService();

String mess = userService.login(users, user);

System.out.println(mess);

init();

}

private static void update() {

System.out.println("\t【注册用户】");

System.out.print("\t请输入用户名:");

String name = key.nextLine();

System.out.print("\t请输入用户密码:");

String password = key.nextLine();

Users users = new Users();

User user = new User(name, password);

UserService userService = new UserService();

String mess = userService.update(users, user);

System.out.println(mess);

init();

}

private static void show() {

System.out.println("用户管理系统");

System.out.println("========================");

System.out.println("【1】注册用户");

System.out.println("【2】用户登录");

System.out.println("【3】密码修改");

System.out.println("【0】退出");

System.out.println("========================");

}

}

完成!!!!

使用java基础完成一个简单的控制台输入的用户管理(包括用户注册 登录 修改密码 及一些相关校验)

本内容不代表本网观点和政治立场,如有侵犯你的权益请联系我们处理。
网友评论
网友评论仅供其表达个人看法,并不表明网站立场。