string - 首字母大写。MySQL的
在MySQL的说法中,有没有人知道这个TSQL的等价物?
我想把每个条目的第一个字母大写。
UPDATE tb_Company SET CompanyIndustry = UPPER(LEFT(CompanyIndustry, 1))
+ SUBSTRING(CompanyIndustry, 2, LEN(CompanyIndustry))
Chin asked -08-12T13:56:08Z
13个解决方案
237 votes
它几乎相同,你只需要更改为使用CONCAT()函数而不是+运算符:
UPDATE tb_Company
SET CompanyIndustry = CONCAT(UCASE(LEFT(CompanyIndustry, 1)),
SUBSTRING(CompanyIndustry, 2));
这将转hello到Hello,wOrLd到WOrLd,BLABLA到BLABLA等。如果你想要大写第一个字母和小写另一个,你只需要使用LCASE函数:
UPDATE tb_Company
SET CompanyIndustry = CONCAT(UCASE(LEFT(CompanyIndustry, 1)),
LCASE(SUBSTRING(CompanyIndustry, 2)));
请注意,UPPER和UCASE做同样的事情。
Vincent Savard answered -08-12T13:56:37Z
38 votes
Vincents对大写第一封信的出色回答非常适用于整个列字符串的首字母大写。
但是,如果你想在表格列的字符串中大写字母的第一个字母怎么办?
例如:"阿比维尔高中"
我还没有在Stackoverflow中找到答案。 我不得不拼凑一些我在谷歌找到的答案,为上面的例子提供了可靠的解决方案。 它不是本机功能,而是用户创建的MySQL版本5+允许的功能。
如果您在MySQL上拥有Super / Admin用户状态或者在您自己的计算机上安装了本地mysql,您可以创建一个FUNCTION(如存储过程),它位于您的数据库中,并且可以在以后的所有SQL查询中使用。 D b。
我创建的函数允许我使用这个我称之为" UC_Words" 就像MySQL的内置本机函数一样,这样我就可以像这样更新一个完整的列:
UPDATE Table_name
SET column_name = UC_Words(column_name)
要插入功能代码,我在创建函数时更改了MySQL标准分隔符(;),然后在函数创建脚本之后将其重置为正常。 我个人也希望输出也是UTF8 CHARSET。
功能创建=
DELIMITER ||
CREATE FUNCTION `UC_Words`( str VARCHAR(255) ) RETURNS VARCHAR(255) CHARSET utf8_general_ci
BEGIN
DECLARE c CHAR(1);
DECLARE s VARCHAR(255);
DECLARE i INT DEFAULT 1;
DECLARE bool INT DEFAULT 1;
DECLARE punct CHAR(17) DEFAULT ' ()[]{},.-_!@;:?/';
SET s = LCASE( str );
WHILE i < LENGTH( str ) DO
BEGIN
SET c = SUBSTRING( s, i, 1 );
IF LOCATE( c, punct ) > 0 THEN
SET bool = 1;
ELSEIF bool=1 THEN
BEGIN
IF c >= 'a' AND c <= 'z' THEN
BEGIN
SET s = CONCAT(LEFT(s,i-1),UCASE(c),SUBSTRING(s,i+1));
SET bool = 0;
END;
ELSEIF c >= '0' AND c <= '9' THEN
SET bool = 0;
END IF;
END;
END IF;
SET i = i+1;
END;
END WHILE;
RETURN s;
END ||
DELIMITER ;
这适用于输出字符串中多个单词的大写首字母。
假设您的MySQL登录用户名具有足够的权限 - 如果没有,并且您无法在个人计算机上设置临时数据库来转换表格,请询问您的共享主机提供商是否为您设置此功能。
Martin Sansone - MiOEE answered -08-12T13:58:24Z
17 votes
您可以使用UCASE(),MID()和CONCAT()的组合:
SELECT CONCAT(UCASE(MID(name,1,1)),MID(name,2)) AS name FROM names;
Wouter Dorgelo answered -08-12T13:58:52Z
8 votes
mysql> SELECT schedule_type AS Schedule FROM ad_campaign limit 1;
+----------+
| Schedule |
+----------+
| ENDDATE |
+----------+
1 row in set (0.00 sec)
mysql> SELECT CONCAT(UCASE(MID(schedule_type,1,1)),LCASE(MID(schedule_type,2))) AS Schedule FROM ad_campaign limit 1;
+----------+
| Schedule |
+----------+
| Enddate |
+----------+
1 row in set (0.00 sec)
[/doc/refman/5.0/en/string-functions.html#function_mid]
Root answered -08-12T13:59:25Z
5 votes
[/tools/tool.php?id=201]
如果列中有多个单词,则此操作将不起作用,如下所示。在这种情况下,上面提到的UDF可能有所帮助。
mysql> select * from names;
+--------------+
| name |
+--------------+
| john abraham |
+--------------+
1 row in set (0.00 sec)
mysql> SELECT CONCAT(UCASE(MID(name,1,1)),MID(name,2)) AS name FROM names;
+--------------+
| name |
+--------------+
| John abraham |
+--------------+
1 row in set (0.00 sec)
或许这个会有所帮助......
[/mysqludf/lib_mysqludf_str#str_ucwords]
shantanuo answered -08-12T14:00:20Z
2 votes
这很好用。
UPDATE状态SET name = CONCAT(UCASE(LEFT(name,1)), LCASE(SUBSTRING(name,2)));
Abhinav Sahu answered -08-12T14:00:55Z
1 votes
UPDATE tb_Company SET CompanyIndustry = UCASE(LEFT(CompanyIndustry, 1)) +
SUBSTRING(CompanyIndustry, 2, LEN(CompanyIndustry))
Jasdeep Singh answered -08-12T14:01:14Z
1 votes
创造一个功能:
CREATE DEFINER=`root`@`localhost` FUNCTION `UC_FIRST`(`oldWord` VARCHAR(255))
RETURNS varchar(255) CHARSET utf8
RETURN CONCAT( UCASE( LEFT(oldWord, 1)), LCASE(SUBSTRING(oldWord, 2)))
使用功能
UPDATE tbl_name SET col_name = UC_FIRST(col_name);
Florin answered -08-12T14:01:49Z
1 votes
如果有人试图将每个单词用空格分开...
CREATE FUNCTION response(name VARCHAR(40)) RETURNS VARCHAR(200) DETERMINISTIC
BEGIN
set @m='';
set @c=0;
set @l=1;
while @c <= char_length(name)-char_length(replace(name,' ','')) do
set @c = @c+1;
set @p = SUBSTRING_INDEX(name,' ',@c);
set @k = substring(name,@l,char_length(@p)-@l+1);
set @l = char_length(@k)+2;
set @m = concat(@m,ucase(left(@k,1)),lcase(substring(@k,2)),' ');
end while;
return trim(@m);
END;
CREATE PROCEDURE updateNames()
BEGIN
SELECT response(name) AS name FROM names;
END;
结果
+--------------+
| name |
+--------------+
| Abdul Karim |
+--------------+
Jahir islam answered -08-12T14:02:19Z
0 votes
这应该很好地工作:
UPDATE tb_Company SET CompanyIndustry =
CONCAT(UPPER(LEFT(CompanyIndustry, 1)), SUBSTRING(CompanyIndustry, 2))
Chris Hutchinson answered -08-12T14:02:59Z
0 votes
UPDATE users
SET first_name = CONCAT(UCASE(LEFT(first_name, 1)),
LCASE(SUBSTRING(first_name, 2)))
,last_name = CONCAT(UCASE(LEFT(last_name, 1)),
LCASE(SUBSTRING(last_name, 2)));
sandeep kumar answered -08-12T14:03:20Z
0 votes
select CONCAT(UCASE(LEFT('CHRIS', 1)),SUBSTRING(lower('CHRIS'),2));
上述声明可用于首字母CAPS,其余为小写。
Aamir Khan answered -08-12T14:03:50Z
-1 votes
Uso algo simples assim;)
DELIMITER $$
DROP FUNCTION IF EXISTS `uc_frist` $$
CREATE FUNCTION `uc_frist` (str VARCHAR(200)) RETURNS varchar(200)
BEGIN
set str:= lcase(str);
set str:= CONCAT(UCASE(LEFT(str, 1)),SUBSTRING(str, 2));
set str:= REPLACE(str, ' a', ' A');
set str:= REPLACE(str, ' b', ' B');
set str:= REPLACE(str, ' c', ' C');
set str:= REPLACE(str, ' d', ' D');
set str:= REPLACE(str, ' e', ' E');
set str:= REPLACE(str, ' f', ' F');
set str:= REPLACE(str, ' g', ' G');
set str:= REPLACE(str, ' h', ' H');
set str:= REPLACE(str, ' i', ' I');
set str:= REPLACE(str, ' j', ' J');
set str:= REPLACE(str, ' k', ' K');
set str:= REPLACE(str, ' l', ' L');
set str:= REPLACE(str, ' m', ' M');
set str:= REPLACE(str, ' n', ' N');
set str:= REPLACE(str, ' o', ' O');
set str:= REPLACE(str, ' p', ' P');
set str:= REPLACE(str, ' q', ' Q');
set str:= REPLACE(str, ' r', ' R');
set str:= REPLACE(str, ' s', ' S');
set str:= REPLACE(str, ' t', ' T');
set str:= REPLACE(str, ' u', ' U');
set str:= REPLACE(str, ' v', ' V');
set str:= REPLACE(str, ' w', ' W');
set str:= REPLACE(str, ' x', ' X');
set str:= REPLACE(str, ' y', ' Y');
set str:= REPLACE(str, ' z', ' Z');
return str;
END $$
DELIMITER ;
Hton answered -08-12T14:04:20Z