python正则表达式之re模块其他方法
1:search(pattern,string,flags=0)
在一个字符串中查找匹配
2:findall(pattern,string,flags=0)
找到匹配，返回所有匹配部分的列表
In [1]: import reIn [2]: str1 = 'imoooc videonum = 1000'In [3]: str1.find('1000')Out[3]: 18In [4]: info = re.search(r'\d+',str1)In [5]: infoOut[5]: <_sre.SRE_Match object; span=(18, 22), match='1000'>In [6]: info.grinfo.groupinfo.groupdict info.groupsIn [6]: info.group()Out[6]: '1000'In [7]: str1 = 'imoooc videonum = 10000'In [8]: info = re.search(r'\d+',str1)In [9]: infoOut[9]: <_sre.SRE_Match object; span=(18, 23), match='10000'>In [10]: info.group()Out[10]: '10000'In [11]: str2 = 'c++=100, java=90, python=80'In [12]: info = re.search(r'\d+',str2)In [13]: infoOut[13]: <_sre.SRE_Match object; span=(4, 7), match='100'>In [14]: info.group()Out[14]: '100'In [15]: info = re.findre.findall re.finditer In [15]: info = re.findall(r'\d+',str2)In [16]: infoOut[16]: ['100', '90', '80']In [17]: sum([int(x) for x in info])Out[17]: 270
3.sub(pattern,repl,string,count=0,flags=0)
将字符串中匹配正则表达式的部分替换为其他值
4.split(pattern,string,maxsplit=0,flags=0)
根据匹配分割字符串，返回分割字符串组成的列表
In [22]: str3 = 'imooc videonum = 1000'In [24]: info = re.sub(r'\d+','1001',str3)In [25]: infoOut[25]: 'imooc videonum = 1001'In [26]: def add1(match):....:val = match.group()....:num = int(val)+1....:return str(num)....: In [27]: str3Out[27]: 'imooc videonum = 1000'In [28]: re.sub(r'\d+',add1,str3)Out[28]: 'imooc videonum = 1001'
In [36]: str4 = 'imooc:C C++ Java Python'In [37]: re.sre.search re.sre_compile re.subre.sysre.split re.sre_parse re.subn In [37]: re.split(r':| ',str4)Out[37]: ['imooc', 'C', 'C++', 'Java', 'Python']In [38]: re.split(r':| |,',str4)Out[38]: ['imooc', 'C', 'C++', 'Java', 'Python']In [39]:
