问题补充:
已知集合A={x|x=cos((2n-1)π/m)^2,n∈Z},当m为4022时,集合A的元素个数为
答案:
x=cos((2n-1)π/m)^2是一个周期为π的函数,
当n=1时,x=cos(π/4022)^2=[1+cos(π/)]/2
当n=时,x=cos(4023π/4022)^2=cos(π+π/4022)^2=[-cos(π/4022)]^2=cos(π/4022)^2
时间:2022-03-25 04:43:23
已知集合A={x|x=cos((2n-1)π/m)^2,n∈Z},当m为4022时,集合A的元素个数为
x=cos((2n-1)π/m)^2是一个周期为π的函数,
当n=1时,x=cos(π/4022)^2=[1+cos(π/)]/2
当n=时,x=cos(4023π/4022)^2=cos(π+π/4022)^2=[-cos(π/4022)]^2=cos(π/4022)^2